Days since beginning: 1067
You can be notified of when this site is updated!
At: Dec 04 2008 23:00Z
|
Thursday, March 13, 2008 - 21:42:55 ET
A while back I posed the question "Does an airplane in 45° bank experience more G forces than a slower one?" The quick answer: No. The G forces (or load factor) on the aircraft does not change based on the speed you are flying. The equation to calculate load factor (n) is as follows: ![]() Where Theta is the angle of bank. Since the angle of bank determines the load factor and not speed, a faster aircraft at 45° will experience the same load factor of a slower aircraft at the same angle of bank. The only thing that is different is the radius of the turn. A faster moving aircraft will have a larger turn radius at the same angle of bank than a slower aircraft. In all instances we're talking about true air speed (TAS).
So lets use two aircraft. A Cessna 172, and a Piper Seminole. Both are excecuting a 45° bank turn. The 172 at 90KTAS and the Seminole at 130KTAS: Cessna:
Seminole:
This is important information to know, especially if you are flying in canyons or other places with limited area to maneuver. If you need to turn 180° in the smallest amount of distance, its best to slow down before executing the turn (see comments). Don't forget! Your stall speed increases as the angle of bank increases. I was never good at math, so please correct me if iIm wrong. The formula states "velocity" and not speed. So I'm unsure if I can use KTAS or if I need to convert that into feet per second. Oh and where did I get 11.29? See the bottom of this page. Comments (6) | Permalink | Category: Aerodynamics, Training
|
|